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The value of the integral $\displaystyle{}\int_{-1}^1 \dfrac{x^2}{1+x^2} \sin x \sin 3x \sin 5x dx$ is

1. $0$
2. $\frac{1}{2}$
3. $– \frac{1}{2}$
4. $1$
in Calculus
recategorized | 30 views
+1
$0$?
+1
yes