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The value of the definite integral $\int_0^{\pi} \mid \frac{1}{2} + \cos x \mid dx$ is

  1. $\frac{\pi}{6} + \sqrt{3}$
  2. $\frac{\pi}{6} - \sqrt{3}$
  3. $0$
  4. $\frac{1}{2}$
in Calculus
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$0$ ??

1 Answer

2 votes
Answer is A.

| ½ + cosx | will be positive(>=0) in the interval [0,2pi/3],

while negative(<0) in the interval [2pi/3,pi].

Rest integrating the terms is straight forward.

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