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3 votes
3 votes

Following Multiplexer circuit is equivalent to

  1. Sum equation of full adder
  2. Carry equation of full adder
  3. Borrow equation for full subtractor
  4. Difference equation of a full subtractor
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2 Answers

5 votes
5 votes

$Y= A'B'C + A'BC' + AB'C' + ABC$

$Y= A\  xor \ B \ xor   \ C$

$Y= \sum(1,2,4,6,7)$, difference equation of full subtractor.

Hence Option d) is correct

2 votes
2 votes
The output Y of the given MUX is the equation for the difference of a full subtractor and Sum of a Full Adder.
Y is the difference between A and B where C is the Barrow.
Y is the Sum of A and B where C is the Carry_in.

Y = B’A’C + B’AC’ + BA’C’ + BAC
Y = (A ⊕ B ⊕ C)
Answer:

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