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Kenneth Rosen Edition 7 Exercise 6.3 Question 16 (Page No. 413)

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elements.nCr where n=10 and  select odd number of set=(1,3,5,7,9)

 set of 1 element select from 10 number=10C1

 set of 1 element select from 10 number=​​​​​​​10C3

 set of 1 element select from 10 number=​​​​​​​10C5

 set of 1 element select from 10 number=​​​​​​​10C7

 set of 1 element select from 10 number=​​​​​​​10C9

10C1 + 10C3 + 10C5 + 10C7 + 10C9 = 512.
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