Ans : (B)
Let x1,x2,x3,x4 represents 3 different triangles 1,2,3,4.
Hence this problem is identical to distributing 8 balls among x1,x2,x3,x4 such that each will get alt least one ball
i.e x1+x2+x3 +x4 = 8 where x1 ≥ 1; x2 ≥ 1;x3 ≥ 1;x4 ≥ 1;
= > (x1-1) + (x2-1) + (x3-1) +(x4 -1) = 4
Now let p = x1-1; q= x2-1;r= x3-1;s=x4-1;
Hence given eqn reduces to : p+q+r+s = 4 where p,q,r,s ≥ 0
solution to this problem = (n+r-1)Cr = (4+4 - 1)C4 = 7C4 = 35