1 1 vote My answer is coming 0. Please explain. Calculus integration calculus + – Utk 3.3k views answer comment Share Follow Print See all 8 Comments 8 8 Comments reply Show 5 previous comments Arjun commented Jan 12, 2016 reply Follow flag yes, split the integral to 4 parts- since both sin and cos are positive from 0 - $\pi/2$, use this integral and multiply by 4. 2 2 replyShare resuscitate commented Jan 12, 2016 reply Follow flag yes yes answer is 8..sorry..anser is 8.i just calculated it. :) previously i did silly thing,basically i didnot calculated it,as there is no qs of pi,so ans i thought will be 0..answer is 8 only.4 ranges. 0 to pi/2 , pi/2 to pi , pi to 3pi/4,3pi/4 to pi.first 0 to pi/2 (sinx +cosx) ,then pi/2 to pi (-sinx + cosx) ,then pi to 3pi/4 ( -sinx - cosx) and lastly 3pi/4 to pi (-sinx +cosx ) ...by integrating those and applying ranges answer will be 8 only 2 2 replyShare Abhishek_Kumar commented Jan 12, 2016 reply Follow flag Its Simple just draw the graph for this. You will find (|Sinx|+|Cosx|) is always greater than 1. So value of [|Sinx|+|Cosx|] will always be 1. So 0 to 2pie the value will be 1*2Pie. 0 0 replyShare Please log in or register to add a comment.
Best answer 8 8 votes ans 8 richa116 answered Jan 12, 2016 • selected Jan 12, 2016 by Arjun richa116 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Its Simple just draw the graph for this. You will find (|Sinx|+|Cosx|) is always greater than 1. So value of [|Sinx|+|Cosx|] will always be 1. So 0 to 2pie the value will be 1*2Pie. Abhishek_Kumar answered Jan 12, 2016 Abhishek_Kumar comment Share Follow 0 reply Please log in or register to add a comment.
