0 0 votes The dimension of the real vector space $V=\{f:(-1,1)\rightarrow\mathbb{R}|f$ is infinitely differentiable on $(-1,1)$ and $f^{(n)}(0)=0$ for all $n\geq 0\}$ is $0$ $1$ greater than one, but finite infinite Linear Algebra tifrmaths2021 linear-algebra functions + – soujanyareddy13 466 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
