in Set Theory & Algebra
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Does the given solution is correct:

When S is symmetric and transitive, if S contain (3,1),(1,3) then (3,3) should also be present form transitivity.

 

Please verify the solution.

in Set Theory & Algebra
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4 Comments

@GateOverflow04 Bro the Relation S is wrong because in the question they said S is symmetric and transitive but S  doesnt have (3,3) pair as

( 3 S 1 ),(1 S 3 ) so according to transtive property ( 3 S 3 ) should be present

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would (1,1) not be in S ?
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@ankitgupta.1729 hi

i saw some one calling you "sir” in one of the answers so im also sticking to this convention 😅

 

yes sir (1,1) should also be present in S 

because if we see the other way (1,3) (3,1) so from transitivity (1,1) should be present in S

 

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1 Answer

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The best way to solve this question is by taking counter example

EDIT : I forgot to write (a,a) in set S it's from transitive property (a,c),(c,a) so (a,a) should be present in S

edited by

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thanks you !!
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