@GateOverflow04 Bro the Relation S is wrong because in the question they said S is symmetric and transitive but S doesnt have (3,3) pair as

( 3 S 1 ),(1 S 3 ) so according to transtive property ( 3 S 3 ) should be present

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Overflow04
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in Set Theory & Algebra
Aug 23

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Does the given solution is correct:

When S is symmetric and transitive, if S contain (3,1),(1,3) then (3,3) should also be present form transitivity.

Please verify the solution.

@GateOverflow04 Bro the Relation S is wrong because in the question they said S is symmetric and transitive but S doesnt have (3,3) pair as

( 3 S 1 ),(1 S 3 ) so according to transtive property ( 3 S 3 ) should be present

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