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A xor B in Set

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2 Answers

Best answer
1 1 vote
Operation  |A-B|    |A EXOR B|  |A| + |B|  |A$\bigcup$B|
Max Value  A  |A|+|B|     |A| + |B|  |A| + |B|
Min value  $\Phi$  $\Phi$  2|A| or 2|B|  |A| or |B|



So, option D

• selected by
1 1 vote

|A-B| = |A| - |A∩B|

|A⊕ B| = |A∪B| - |A∩B| =  |A| + |B| - 2|A∩B| = |A| - |A∩B| + |B| - |A∩B| = |A-B| + |B-A|

|A| + |B|

|A∪B| = |A| + |B| - |A∩B|

SO answer will be  4 

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