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Recent questions tagged usergate2005
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Self Doubt on GATE2005-65
https://gateoverflow.in/1388/gate2005-65 $\text{In this question, what will be the number of }$ $\textbf{cycles}$ $\text{needed during execution cycle of instruction}$ $\text{According to me I am getting 6 cycles. Please tell what could be the correct answer for it}$
https://gateoverflow.in/1388/gate2005-65$\text{In this question, what will be the number of }$ $\textbf{cycles}$ $\text{needed during execution cycle of instruction}$$\te...
!KARAN
617
views
!KARAN
asked
Sep 9, 2018
CO and Architecture
usergate2005
usermod
co-and-architecture
addressing-modes
self-doubt
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–
0
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0
answers
2
toc 2005
Consider the following expression grammar. The semantic rules for expression calculation are stated next to each grammar production. E → number E.val = number. val | E '+' E E(1).val = E(2).val + E(3).val | E ' ' E E(1).val = ... of a shift over a reduce action (D). It detects shift-reduce conflict, and resolves the conflict in favor of a reduce over a shift action
Consider the following expression grammar. The semantic rules for expression calculation are stated next to each grammar production.E → number E.val = number. val | E...
turendar
461
views
turendar
asked
Sep 6, 2018
Theory of Computation
usergate2005
usermod
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–
0
votes
0
answers
3
#OS Gate IT 2005 Self Doubt.
Original question - https://gateoverflow.in/3823/gate2005-it-62 Two shared resources R1 and R2 are used by processes P1 and P2. Each process has a certain priority for accessing each resource. Let Tij denote the priority of Pi for accessing Rj. A ... explain how to interpret this line - A process Pi can snatch a resource Rh from process Pj if Tik is greater than Tjk
Original question - https://gateoverflow.in/3823/gate2005-it-62 Two shared resources R1 and R2 are used by processes P1 and P2. Each process has a certain priority for ac...
iarnav
506
views
iarnav
asked
Aug 22, 2018
Operating System
usermod
operating-system
usergate2005
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–
1
votes
1
answer
4
#Algortihms Gate 2000 Question Self Doubt
Source - Here Let G be an undirected graph. Consider a depth-first traversal of G, and let T be the resulting depth-first search tree. Let u be a vertex in G and let v be the first new (unvisited) vertex visited after visiting u in ... being, since (u,v) is an edge in G therefore they can only be SIBLINGS in DFS tree and never have descendant relationship?
Source - HereLet G be an undirected graph. Consider a depth-first traversal of G, and let T be the resulting depth-first search tree. Let u be a vertex in G and let v be ...
iarnav
891
views
iarnav
asked
May 29, 2018
Algorithms
algorithms
graph-algorithms
usermod
usergate2005
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–
5
votes
1
answer
5
#Algorithms Gate 2005 Question Self Doubt.
Source of the question - here A sink in a directed graph is a vertex i such that there is an edge from every vertex $j ≠ i $ to i and there is no edge from i to any other vertex. A directed graph G with n vertices is represented by ... the diagonal elements in adjacency matrix is = 0. You can take a Graph with 4 vertices and make anyone of them as a sink.
Source of the question - hereA sink in a directed graph is a vertex i such that there is an edge from every vertex $j ≠ i $ to i and there is no edge from i to any othe...
iarnav
1.2k
views
iarnav
asked
May 23, 2018
Algorithms
algorithms
graph-algorithms
usergate2005
usermod
+
–
6
votes
1
answer
6
GATE CE 2005 linear algebra
Consider the system of linear equations A(n*n)X(n*1) = λ(n*1) where λ is a scalar. Let (λi , Xi) be an eigen pair of an eigen value and its corresponding eigen vector for a real matrix A. Let I be a n*n unit matrix. Which one of the following statements is ... = A's inverse ) , then mod(λi)=1 for all i. (D) if (A's transpose = A) , then λi is real for all i
Consider the system of linear equations A(n*n)X(n*1) = λ(n*1) where λ is a scalar. Let (λi , Xi) be an eigen pair of an eigen value and its corresponding eigen vector ...
vishwajit_vishnu
2.3k
views
vishwajit_vishnu
asked
Sep 1, 2017
Linear Algebra
engineering-mathematics
eigen-value
linear-algebra
usergate2005
+
–
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