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How to solve this type of question?

asked in Digital Logic by (419 points) 15 29
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1 Answer

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It is a hypothetical 16 bit floating point representation
sign bit =1 bit exponent=7 bit it is excess-64 means add 64 (1000000) in actual exponent 
mantissa=8 bits
no is (0.2 *213)10
= (.001100110011.... *213)  is not normalize
=(.100110011..... *210)  is normalized now 
exponent field = actual exponent + bias= (10+64)=(74)10 =(1001010)2 
 now 8 bits mantissa = 10011001
sign bit field =0 (means positive no)
now put all these values in given format(sign bit-exponent-mantisssa) nd convert it into base-16
=(0100101010011001)2
=(4A99)
 

answered by Veteran (11.8k points) 13 42 139
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