1 1 vote A one bit adder takes 75ns to produce sum and 50 ns to produce carry A 4 bit parallel adder is designed using this type of full adder .the maximum rate of addition per second can be provided by 4 bit parallel adder is A *10^6 , A ? Digital Logic digital-logic + – sid1221 4.8k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply sourav. commented Jul 2, 2017 reply Follow flag is $A=4.45$? 0 0 replyShare joshi_nitish commented Jul 2, 2017 reply Follow flag 4.44?? 0 0 replyShare Please log in or register to add a comment.
Best answer 6 6 votes For one Flip flop Sum Time = 75ns Carry Time = 50ns Consider this four bit parallel adder:- Consider this Time-Action Table:- Time (ns) Action Performed 0 ff0 start working 50 ff0 generate carry for ff1, thus ff1 start working 100 ff1 generate carry for ff2, thus ff2 start working 150 ff2 generate carry for ff3, thus ff3 start working 225 ff3 generate the final result. Calculation Part:- From above table we can see that for performing 1 addition opr it require 225ns 1 addition ---- 225ns 1/(225 * 10^-9) -------- 1 second 4.44 * 10 ^6 addition ------- 1 second So, the value of A is 4.44. Shubhanshu answered Jul 2, 2017 • selected Jul 2, 2017 by sourav. Shubhanshu comment Share Follow See all 2 Comments 2 2 Comments reply $ruthi commented Jul 14, 2017 reply Follow flag can it be 3.33 * 10^6 if we consider sum propagation? 0 0 replyShare Shubhanshu commented Jul 14, 2017 reply Follow flag Yes instead of propagating carry if u propagate sum then final result that generated will be at 300ns. So yes it will be 3.33 *10^6. But why? 0 0 replyShare Please log in or register to add a comment.