The Gateway to Computer Science Excellence
0 votes
462 views

If we solve this we will get total 4 eigen vectors,but as we know that this is of 2 degree matrix so only 2 will exist.So can i say that from these four pairs by using nay 2 ,i can derive the other?If yes,then how?

in Linear Algebra by Boss (25.3k points) | 462 views
0
answer will be (A)...and why you will get 4 eigen vectors, only 2 eigen vectors corresponding to 2 eigen values....if you are saying in this sense """""one time take x as arbitary next time take y as arbitary""""".....it will not make 4 eigen vector, it is still two eigen vectors, because ultimately you will take out common arbitary...

i dont know if you understand what i am saying..
0
Answer is both a and c and it was marks to all
0
how option 'c' could be answer??....in second pair of eigenvector [0 1], it is not possible because here x=0 and since either x or y is linearly dependent on other then other should also be 0...
0
what will be its eigen values and vector please explain
0
here , there will be two eigen vectors ({1,-j} corresponding to eigen value i  and {j,-1} corresponding value -i).

1 Answer

0 votes

The answer is A

,Since the eigen value is j, and -j finding the corresponding eigen vector, which gives  {1 -i} and {i,-1} respectively

by (409 points)
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,645 questions
56,563 answers
195,734 comments
101,647 users