1 1 vote ( ∃x(P(x))→∃x(Q(x)) ) → ( ∃x(P(x)→Q(x)) ) ( ∃x(P(x)→Q(x)) ) → ( ∃x(P(x))→∃x(Q(x)) ) Which of the above is valid and for not valid please give me counter example where LHS is true but RHS is false? Mathematical Logic mathematical-logic propositional-logic discrete-mathematics first-order-logic + – rahul sharma 5 1.5k views answer comment Share Follow Print See 1 comment 1 1 comment reply Lakshman Bhaiya commented Jul 28, 2017 reply Follow flag (1) is True and (2) is False 0 0 replyShare Please log in or register to add a comment.
Best answer 1 1 vote 1st statement is valid as there no chances to get T-F possibility. Manu Thakur answered Jul 28, 2017 • selected Jul 28, 2017 by rahul sharma 5 Manu Thakur comment Share Follow See all 2 Comments 2 2 Comments reply IamRishabh commented Jul 29, 2017 reply Follow flag I am not able to get you @manu00x can you explain this using sentence reasoning or anyone else can do that because i am not able to solve such type of question ...thank you 0 0 replyShare rahul sharma 5 commented Oct 27, 2017 reply Follow flag @manu00x .Why will RHS fails for the c object? In the RHS implication the hypothesis will be false ,so RHS should be true? 0 0 replyShare Please log in or register to add a comment.
1 1 vote Therefore , I is Valid II is not valid Aashish S answered Aug 21, 2017 Aashish S comment Share Follow 0 reply Please log in or register to add a comment.
