Register

Integration

851 views
5 5 votes

1 Answer

Best answer
3 3 votes

now, we can see that there is atleast one point in (1,2) where curve is cutting x axis..

this means (1+cos8x)(ax2+bx+c) = 0 for some x$\epsilon$(1,2)....., but,

(1+cos8x)$\neq$0 , since 1+cos8x>=1 $\forall$ x , therefore

(ax2+bx+c)=0 for some x$\epsilon$(1,2)...

hence (ax2+bx+c) has atleast one root in (0,2)..

• selected by
Voting & Accepting an answer helps improve the community
← Previous · process synchronizat...Next → · #Lexical_Analysis
← Previous in category · Differential calculu...Next in category → · Maxima and minima
Position:
Show:

Related questions

2 2 votes
4 4 answers
848
848 views
GO Classes asked Jul 5, 2025
848 views
GO CLASSES DPP | Calculus | Integration | GATE CE
The integral $\int_0^1 \frac{d x}{\sqrt{(1-x)}}$ is equal to
2 2 votes
2 2 answers
502
502 views
GO Classes asked Jul 5, 2025
502 views
GO CLASSES DPP | Calculus | Integration | GATE CE
The value of the following improper integral is $\int_0^1 x \ln x$$1 / 4$ $0$ $-1 / 4$ $1$
0 0 votes
1 1 answer
1.0k
1.0k views
srestha asked Nov 16, 2018
1,021 views
Integration
$\int_{0}^{1}\frac{x^{\alpha }-1}{logx}dx$ where $\alpha>0$
0 0 votes
1 answers 1 answer
797
797 views
srestha asked Oct 6, 2018
797 views
Integration
Solve$\int_{0}^{\pi }sin^{5}\frac{x}{2}dx$