10 10 votes The maximum value of a such that the matrix below has three linearly independent real eigen vectors is $\begin{pmatrix} -3& 0 &-2 \\ 1& -1 & 0\\ 0& a & 2 \end{pmatrix}$ (a) $\frac{2}{3\sqrt{3}}$ (b) $\frac{1}{3\sqrt{3}}$ (c) $\frac{1+2\sqrt{3}}{3\sqrt{3}}$ (d)$\frac{1+\sqrt{3}}{3\sqrt{3}}$ Linear Algebra engineering-mathematics gate-2015ee + – Ayush Upadhyaya 4.8k views answer comment Share Follow Print See all 5 Comments 5 5 Comments reply Show 2 previous comments eyeamgj commented Oct 4, 2018 reply Follow flag @ srestha MAM I AM GETTING (-27-10√3)/9 ..... 0 0 replyShare Aishvarya Akshaya Vi commented May 27, 2019 reply Follow flag Starting solution. 0 0 replyShare Random_aspirant commented Apr 1, 2024 reply Follow flag can someone explain in English how to solve this? Given solution is too big and not clear 0 0 replyShare Please log in or register to add a comment.
0 0 votes Answer is option b) Aishvarya Akshaya Vi answered May 27, 2019 Aishvarya Akshaya Vi comment Share Follow See all 2 Comments 2 2 Comments reply Aishvarya Akshaya Vi commented May 27, 2019 reply Follow flag I forgot to add the starting of the solution ,here it is 0 0 replyShare Lalo commented Mar 3, 2021 reply Follow flag There is no use of limiting Characteristic polynomial at Maxima point, and this step is redundant. Since we need the maximum value of ‘a’ and we see in our polynomial that greater the value of ‘a’, more the graph(polynomial) would shift above. Hence we need to apply the boundary condition just at the minima point so that it doesn’t go above the x-axis and thus giving 3 distinct solution. 0 0 replyShare Please log in or register to add a comment.