0 votes 0 votes The exponent of 11 in the prime factorization of 300! is 27 28 29 30 the answer is 29.....but what if the question was just factorisation and not prime factorisation is there any difference ? A_i_$_h asked Dec 6, 2017 A_i_$_h 520 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Rishabh Gupta 2 commented Dec 6, 2017 reply Follow Share how to get 29? 0 votes 0 votes abhishek tiwary commented Dec 6, 2017 reply Follow Share like find all factor of 120=2*2*2*3*5=2^3*3^1*5^1 so Factors=(3+1)(1+1)(1+1)=16 so P1^a1*P2^a2.......where p1,p2 are prime so factors=(a1+1)(a2+1) ?? 1 votes 1 votes Anu007 commented Dec 6, 2017 reply Follow Share Multiple of 11 11,22,33,44,55,66,77,88,99,121, till 297(11*27) but here 121 and 242 has two multiple of 11 i.e. 121 = 11*11 and 242 =11*11 *2 so so 27+2= 29 2 votes 2 votes abhishek tiwary commented Dec 6, 2017 i edited by abhishek tiwary Dec 6, 2017 reply Follow Share floor(300/11)+floor(300/121)=27+2=29 1 votes 1 votes Rishabh Gupta 2 commented Dec 6, 2017 reply Follow Share got it @Anu007 sir. 1 votes 1 votes A_i_$_h commented Dec 16, 2017 reply Follow Share my doubt was .....prime factorisation and normal factorisation...makes any difference ? 0 votes 0 votes Please log in or register to add a comment.