0 0 votes The exponent of 11 in the prime factorization of 300! is 27 28 29 30 the answer is 29.....but what if the question was just factorisation and not prime factorisation is there any difference ? Set Theory & Algebra + – A_i_$_h 1.1k views answer comment Share Follow Print See all 6 Comments 6 6 Comments reply Rishabh Gupta 2 commented Dec 6, 2017 reply Follow flag how to get 29? 0 0 replyShare abhishek tiwary commented Dec 6, 2017 reply Follow flag like find all factor of 120=2*2*2*3*5=2^3*3^1*5^1 so Factors=(3+1)(1+1)(1+1)=16 so P1^a1*P2^a2.......where p1,p2 are prime so factors=(a1+1)(a2+1) ?? 1 1 replyShare Anu007 commented Dec 6, 2017 reply Follow flag Multiple of 11 11,22,33,44,55,66,77,88,99,121, till 297(11*27) but here 121 and 242 has two multiple of 11 i.e. 121 = 11*11 and 242 =11*11 *2 so so 27+2= 29 2 2 replyShare abhishek tiwary commented Dec 6, 2017 i edited by abhishek tiwary Dec 6, 2017 reply Follow flag floor(300/11)+floor(300/121)=27+2=29 1 1 replyShare Rishabh Gupta 2 commented Dec 6, 2017 reply Follow flag got it @Anu007 sir. 1 1 replyShare A_i_$_h commented Dec 16, 2017 reply Follow flag my doubt was .....prime factorisation and normal factorisation...makes any difference ? 0 0 replyShare Please log in or register to add a comment.
