ace test series

Question

Comments

10+(1-h1)*110=20

h1=.909

90.90%

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it seems like an ambiguous question

Answer 1

Answer is B

Here, there nothing specified about how we access memory when there is a miss in cache,

So we take Default case

formula: (Memory access time wiithout cache) = (main memory time).

formula: (memory access time with cache) = hit(cache time) + miss(Main memory time)

In this problem.. cache time= 10ns and memory access time with cache =20ns and main memory time=110ns

so simply put the values in formula

20 = h(10)+(1-h)(110)

so we will get h=0.9

and hence answer is (B)=90%