permutation

Question

How many ways are there to seat six people around circular table where two seatings are considered same when everyone has same two neighbors without regard to whether they are left or right neighbors?

Answer 1

Answer is same as number of even permutation of nelements. I.e. (n-1)!/2.

Comments

@digvijay

is it like garland question ?

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How even permutations are (n-1)! / 2 ?

I think total permutations are n!, which should be divided into even and odd i.e. n!/2 & n!/2

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can anyone answer this question??

I am confused. This LINK stats that it should be n!/2 and I agree with that. But the answer give in Rosen book is 60 (Exercise 6.2 Q-45)

Exactly same problem given in Example 20 saying it should be n!/n.

Which one is correct??