The Gateway to Computer Science Excellence
0 votes
If the time taken by a task to get completed is same in the pipeline and non pipeline circuits, then how the time taken to complete the task in non pipeline =  k* time taken to complete the task in pipeline where k is no. of segments in the pipeline?
in CO and Architecture by
edited by | 50 views
If you take one task and execute in non-pipeline and it's corresponding pipelined architecture having k stages each of equal length then the time taken by both will be same.

If the stage delays are different, then for a single task, pipeline will take more time than non Pipelined one.

But if you consider for a *large number of tasks* then you will understand the difference that time taken by pipelined one is much less.

Please log in or register to answer this question.

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
52,215 questions
60,013 answers
94,700 users