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1 1 vote
Let X and Y be two sets having n elements
each. Then the total number of bijective
functions from X and Y is
(A) n (B) 2n
(C) n! (D) 2n

1 Answer

3 3 votes
Bijection means both Onto and One-One.

Now, if we have two sets with $X$ and $Y$ with $N$ elements each, each element from $Y$ has to map exactly $1$ element of $X$.

So, this simplifies your problem to place $N$ different balls to $N$ different boxes, where each box can hold only $1$ ball. In other way, you just have to find out how many ways you can arrange the $N$ elements of $Y$.

This is simple permutation i.e. $N!$.

Do Note – Bijection is only possible between two sets if both have same cardinality.
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