0 votes 0 votes Prove that for any integer n if 3n+2 is even, then n is even , by method of Contraposition. LavTheRawkstar asked Jun 26, 2016 LavTheRawkstar 515 views answer comment Share Follow See 1 comment See all 1 1 comment reply vijaycs commented Jun 26, 2016 reply Follow Share let n = odd, then 2k + 1 = n , 3n + 2 = 3( 2k + 1 ) + 2 = 6k + 3 + 2 = odd. Now if n = even = 2k 3n + 2 = (3 * 2k ) + 2 = 6k + 2 = even . 1 votes 1 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes If we take n = odd here, then 3n + 2 = odd always and If we take n = even here, then 3n + 2 = even always. Kapil answered Jun 27, 2016 • selected Jun 27, 2016 by LavTheRawkstar Kapil comment Share Follow See all 0 reply Please log in or register to add a comment.