1 votes 1 votes Solve the Recurrence Relation S(r) - 6 S(r-1) +8 S(r-2) = 3r; S(0) =8, S(1)=7 Combinatory discrete-mathematics combinatory + – LavTheRawkstar asked Jun 26, 2016 • retagged Jun 27, 2017 by Arjun LavTheRawkstar 1.9k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes S(r) = c1. 4n + c2.2n + 7.3n Now, put the values of S(0) and S(1) to get c1 and c2 Sushant Gokhale answered Sep 11, 2016 • edited Jan 5, 2017 by Sushant Gokhale Sushant Gokhale comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments gauravkc commented Jan 31, 2018 reply Follow Share Can someone give a proper solution to this 0 votes 0 votes rajatmyname commented Feb 28, 2019 reply Follow Share Can you please provide the theory to solve this question? 0 votes 0 votes shashankpant16 commented Nov 26, 2020 reply Follow Share When i solved, i got answer as: S(r) = a.4^n + b.2^n - 3^n+2 Where a = -8 and b = 25, and Particular value will be “-9”. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes S(r)=((17)(2^r))-(3^(r+2)). where r>=2 and S(0)=8 and S(1)=7 manoj0606 answered Dec 13, 2022 manoj0606 comment Share Follow See all 0 reply Please log in or register to add a comment.