0 votes 0 votes In how many ways $10$ different books can be distributed among there student $A, B$ and $C$ such that $A$ must be given at least $1$ book? Combinatory discrete-mathematics combinatory + – Lakshman Bhaiya asked Oct 24, 2018 • edited Oct 24, 2018 by Lakshman Bhaiya Lakshman Bhaiya 375 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Utkarsh Joshi commented Oct 24, 2018 reply Follow Share 3^10-2^10? is it correct?Lakshman Patel RJIT 0 votes 0 votes Lakshman Bhaiya commented Oct 24, 2018 reply Follow Share $3^{10}-2^{10}=58025$ yes can you explain please 0 votes 0 votes Utkarsh Joshi commented Oct 24, 2018 reply Follow Share We can user complement principle here! Cases where A gets atleast one book = total cases - A doesn't get any book Total cases: as each book is distinct each book can be given to A ,B or C. So 3 choices for each book. total 3^10. Cases where A doesn't get any book : same as above but only B and C are two choices so 2^10. 1 votes 1 votes Please log in or register to add a comment.
