0 0 votes In how many ways $10$ different books can be distributed among there student $A, B$ and $C$ such that $A$ must be given at least $1$ book? Combinatory discrete-mathematics combinatory + – Lakshman Bhaiya 751 views answer comment Share Follow Print See all 5 Comments 5 5 Comments reply Show 2 previous comments Utkarsh Joshi commented Oct 24, 2018 reply Follow flag 3^10-2^10? is it correct?Lakshman Patel RJIT 0 0 replyShare Lakshman Bhaiya commented Oct 24, 2018 reply Follow flag $3^{10}-2^{10}=58025$ yes can you explain please 0 0 replyShare Utkarsh Joshi commented Oct 24, 2018 reply Follow flag We can user complement principle here! Cases where A gets atleast one book = total cases - A doesn't get any book Total cases: as each book is distinct each book can be given to A ,B or C. So 3 choices for each book. total 3^10. Cases where A doesn't get any book : same as above but only B and C are two choices so 2^10. 1 1 replyShare Please log in or register to add a comment.
