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ISRO2016 EC Probability

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A person on a trip has a choice between a private car and public transport. The probability of using a private car is $0.45.$ While using public transport, the further choice available are bus and metro. Out of which the probability of commuting by a bus is $0.55.$ In such a situation, the probability (rounded up to two decimals) of using a car, bus and metro respectively would be

  1. $0.45, 0.30$ and $0.25$
  2. $0.45, 0.25$ and $0.30$
  3. $0.45, 0.55$ and $0$
  4. $0.45, 0.35$ and $0.20$

2 Answers

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They have given that probability of choosing car which is 0.45.

And hence probability of choosing public transport=1 -0.45=0.55 which is going to be distributed among Bus and metro.

They have given that out of 0.55, probability of choosing bus = 0.55 * 0.55 = 0.3025=0.30(Approx)

So , probability of choosing metro will be=0.55 * 0.45 =0.2475= 0.25 (Approx)

I think Option A will be Correct.
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