0 0 votes A full adder circuit is implemented using 2-input AND, OR gates; each of which takes 1 unit of delay. If inputs are also available in complements forms, what will be the delay of full adder (in units)? Digital Logic + – rbvummadi 2.1k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply BASANT KUMAR commented Aug 1, 2019 reply Follow flag if we ignore the delay of not gate then i think delay will be 4*1=4 unit 0 0 replyShare srestha commented Aug 4, 2019 reply Follow flag Here NOT gate also required. right?? 0 0 replyShare Please log in or register to add a comment.
0 0 votes $18$ units of delay, Each AND gate requires $1$ bit delay, and NOT required $1$ bit delay. Input present in complemented form, but that will not reduce number of NOT gate. srestha answered Aug 4, 2019 srestha comment Share Follow See all 6 Comments 6 6 Comments reply BASANT KUMAR commented Aug 4, 2019 reply Follow flag ma'am can you explain little bit more how 18 unit???some gate will work in parallel.check one more time. 0 0 replyShare srestha commented Aug 5, 2019 reply Follow flag if some GATE works parallel , what change will shown in output?? 0 0 replyShare BASANT KUMAR commented Aug 5, 2019 reply Follow flag suppose a circuit has two gates which are work in parallel and their delay is 2 unit each then overall delay of the circuit will have 2 unit delay, not 4 unit delay.i think in your solution you considered 18 gates(AND+NOT) and delay =18*1=18 unit. why you consider the delay of those gates which are working simultaneously means in parallel. 0 0 replyShare srestha commented Aug 5, 2019 reply Follow flag yes, ans will be then $6*2=12$ unit right?? 0 0 replyShare BASANT KUMAR commented Aug 5, 2019 reply Follow flag yes 12 unit is right. 0 0 replyShare nick-ilektronics commented Jun 28, 2021 reply Follow flag good afternoon.How can i connect 4 of those full adders for 4 bit 0 0 replyShare Please log in or register to add a comment.