(Closed) Probability, P&C doubt cleared

Question

Question – If there is a bag that has 2 balls, with the colour of the balls being unknown, what is the probability that both turn out to be blue coloured balls?
My doubt – which of the 2 following methods  is correct and why :

1) Both balls can either be blue or other coloured  so, 4 possibilities :  (other, other), (other, blue), (blue, other), (blue, blue) hence $\frac{1}{4}$
or
2) Three possibilities : 0 blue balls, 1 blue ball or 2 blue balls as the order of balls doesn’t matter here hence $\frac{1}{3}$

Comments

How many colors are there? Are all equally likely to be used for both balls?

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Understood my mistake sir, just because outcomes are equal against an event, it doesn’t make them equiprobable. Thank you so much sir.