24 votes 24 votes The Boolean function in sum of products form where K-map is given below (figure) is _______ Digital Logic gate1992 digital-logic k-map normal fill-in-the-blanks + – Kathleen asked Sep 12, 2014 • retagged Apr 19, 2021 by Lakshman Bhaiya Kathleen 5.6k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply set2018 commented Nov 25, 2017 reply Follow Share simple approach: 1) just draw truth table for 3 variables(0 to 7) 2) now set function value acoording to given kmap 3) minimize function now using kmap 5 votes 5 votes Abhineet Singh commented Nov 11, 2020 reply Follow Share i dont get this K-map 0 votes 0 votes Please log in or register to add a comment.
Best answer 27 votes 27 votes Answer - $ABC + B'C' + A'C'$ Expand this $K$ map of $2$ variables $($$4$ cells$)$ to $K$ map of three variable $($$8$ cells$)$ Entries which are non zero are: $A'B'C', AB'C', A'BC'$ and $ABC$ Minimize $SOP$ expression using that $K$ map. ankitrokdeonsns answered Oct 20, 2014 • edited Jul 27, 2018 by Manoja Rajalakshmi A ankitrokdeonsns comment Share Follow See all 14 Comments See all 14 14 Comments reply Arjun commented Oct 21, 2014 reply Follow Share You missed an entry AB'C' 0 votes 0 votes ankitrokdeonsns commented Oct 22, 2014 reply Follow Share A'B'C' + A'B C' + ABC = A'C'(B' + B) + ABC = A'C' + ABC 0 votes 0 votes Arjun commented Oct 22, 2014 reply Follow Share The given K-map has an entry B'C'. So, when you expand with A, it must be AB'C' + A'B'C'. 1 votes 1 votes ankitrokdeonsns commented Oct 22, 2014 reply Follow Share I agree I'll edit the answer finally it comes out as ABC + B'C' + A'C' 0 votes 0 votes Pranabesh Ghosh 1 commented Nov 20, 2016 reply Follow Share @Arjun sir is this ans correct? 0 votes 0 votes air1ankit commented Dec 29, 2017 reply Follow Share how we can expand this K map of 2 variables (4 cells) to K map of three variable (8 cells)????? 0 votes 0 votes arch commented May 17, 2018 reply Follow Share how to convert 2 variable k map to 4 variable k map? 0 votes 0 votes Peeyush Pandey commented Dec 8, 2018 reply Follow Share Convert 2 variable k map to 3 variable k map like this. look b and c at 0,0 fill 1 in new table, at 0,1 fill 0, at 1,0 fill A', at 1,1 fill A 32 votes 32 votes tusharp commented Apr 14, 2019 reply Follow Share What he has explained is correct. If you don't know what he is saying, just check how to construct a characteristic table of a flip flop. You will get the answer. 0 votes 0 votes Lakshman Bhaiya commented Oct 14, 2019 reply Follow Share @Peeyush Pandey Nice approach!! 0 votes 0 votes CSHuB commented Jan 22, 2020 reply Follow Share Is this thing valid? $\mathbf{A'(BC+B'C') = A'}$ Can someone please check this?? 0 votes 0 votes Peeyush Pandey commented Feb 6, 2020 reply Follow Share make a characteristic table for 3 variables and check all 8 combinations, if L.H.S. matches R.H.S for every combination then it is valid else not. 0 votes 0 votes Overflow04 commented Sep 7, 2022 reply Follow Share @CSHuB No it is wrong. (BC)’ = B’ + C’ . i.e. A’ (BC + (BC)’ ) => A’ (BC + B’ + C’) = > A’ To verify draw the truth table. 1 votes 1 votes sagarmittal commented Nov 27, 2023 reply Follow Share Resultant K-map 0 votes 0 votes Please log in or register to add a comment.
29 votes 29 votes B'C'+ BC'A'+ ABC = C'(B' + BA') + ABC = C'(A'+ B') + ABC = A'C'+ B'C'+ ABC Arjun answered Oct 21, 2014 • edited Aug 6, 2018 by srestha Arjun comment Share Follow See all 2 Comments See all 2 2 Comments reply akash.dinkar12 commented May 21, 2017 reply Follow Share sir, this is variable entrant map??? right 2 votes 2 votes Veenit commented Sep 18, 2019 reply Follow Share Yes, this is directly from variable entrant map. 0 votes 0 votes Please log in or register to add a comment.
7 votes 7 votes Alternate Method:- C B 0 1 0 1 0 1 A’ A Step1: (Mark all the variables in Cell as 0) C B 0 1 0 1 0 1 0 0 f0=B’C’ ---- i Step2: Minterm for variable A’. (Mark minterm obtained for 1 as Don’t Care and target variable as 1) C B 0 1 0 X 0 1 1 0 fA’=A’C’ --- ii Step2: Minterm for variable A. (Mark minterm obtained for 1 as Don’t Care and target variable as 1) C B 0 1 0 X 0 1 0 1 fA=ABC ---iii f=ABC+A’C’+B’C’ (Ans) Avik10 answered Mar 15, 2017 Avik10 comment Share Follow See all 0 reply Please log in or register to add a comment.
7 votes 7 votes Variable Entered Map: $B$ $C$ $f$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $0$ $A'$ $1$ $1$ $A$ $\downarrow$ $A$ $B$ $C$ $f$ $0$ $0$ $0$ $1$ $0$ $0$ $1$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $1$ $0$ $1$ $0$ $0$ $1$ $1$ $0$ $1$ $0$ $1$ $1$ $0$ $0$ $1$ $1$ $1$ $1$ $f=\Sigma (0,2,4,7)$ $f=A'B'C'+A'BC'+AB'C'+ABC$ $f= ABC+A’C’+B’C’$ KUSHAGRA गुप्ता answered Mar 11, 2020 • edited Jan 7, 2023 by Pranavpurkar KUSHAGRA गुप्ता comment Share Follow See all 2 Comments See all 2 2 Comments reply raj26 commented May 17, 2021 reply Follow Share @ Kushagra gupta sir,we need to minimize this expression into : ABC+B’C’+A’C’ 0 votes 0 votes raj26 commented May 17, 2021 reply Follow Share @ Kushagra gupta sir,we need to minimize this expression into as below : A’B’C’+A’BC’+AB’C’+ABC =A’C’(B’+B)+AB’C’+ABC = A’C’+AB’C’+ABC = C’(A’+AB’)+ABC = C’(A+A’)(A’+B’)+ABC = C’(A’+B’)+ABC = ABC+A’C’+B’C’ 1 votes 1 votes Please log in or register to add a comment.