Recent posts tagged interview

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292 views
R0 <= R0 +R1The sequence of instruction take place I Cycle : R1 out , SinII Cycle: Ro out , TinIII Cycle: Sout , Tout , ALU , Rin therefore 3 cycle required
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if E has two production for itself then we have to check for right and left .Please give an example for this, thanks :)
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2,397 views
so the hardware is not available for instruction 3 i.e registers r1 and r2 ?
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3,140 views
answer is b. without reentry the system will not be in deadlock. it will be just not be able to do usefull work. it will be in spin lock.
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14,233 views
NO.Priority Inversion Problem :Lets Consider one example: Tasks:High Priority (H) Medium Priority (M)Low Priority (L)and a lock X, may be semaphore_lock(X).(lock is requi...
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4,238 views
R1 &cap; R2 != &empty;. This makes the decomposition lossless join and as all the attributes are prime, so whatever is the decomposition, it will be 2NF and 3NF. So, Ans ...
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4,434 views
Accept a language $L$ also means shouldn't accept anything not in $L$. Actually non recursively enumerable languages are not accepted by turing machineHere, 'recognized'...
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6,307 views
where is the dead state ??
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5,802 views
@iaser, can you explain your answer?
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10,102 views
N bit sequence detector need atleast N state to accept N bit sequence .....http://www.edwardbosworth.com/My5155_Slides/Chapter07/DesignOfSequenceDetector.pdf
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8,422 views
Out of syllabus now
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4,868 views
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4,550 views
The answer for this question is A . Only one circuit is required (only a not gate ) .
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2,094 views
NO error but it is illegal initialization
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2,950 views
Yes. And it should mean the 1st one. That's the beauty of English grammar :P
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3,635 views
starting with 001100110011 means alternative sequence of process P and Q..Process P should start execution so at W, P(s) where S=1..to get alternate sequence X and Y are...
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7,731 views
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3,640 views
The no of vertices in a graph containing 21 edges, 3 vertices of degree 4 and other vertices of degree 3 are:a) 10b) 13c) 11d) NoneSum of degrees of vertices= 2*no of edg...
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3,349 views
There is no limit on a large value being considered. f(n)= n^0.0000001 = n^(10^-7)g(n)=lg n(base 2)n= 10^8 f(n)= 1.000001842 , g(n)=26.565Now, I take n = 10^(10^8)f(n) ...
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2,161 views
Instead of finding a function 'f' for the first MUX (in terms of z,x and y) and the second MUX (in terms of f , x and y), we can logically find out the answer.We can put ...
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1,211 views
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9,661 views
If $x$ is real and $\mid x^2-2x+3 \mid = 11$, then possible values of $\mid -x^3+x^2-x\mid$ include$2, 4$$2, 14$$4, 52$$14, 52$
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