1 votes
1
The __________ command will show you the translation table containing all the active $NAT$ entries.show ip nat translationsshow ip nat tlshow ip nat statesnone of the opt...
0 votes
2
In an $\text{IPv6}$ header, the traffic class field is similar to the ________ field in the $\text{IPv4}$ header.$TOS$ fieldFragmentation fieldFast SwitchingOption field...
0 votes
3
In HTML, $<\text{map}>$ tag is used fordefining a path between two nodes in an imagedefining clickable region in an imagehighlighting an area in an imagedefining the site...
2 votes
4
1 votes
6
2 votes
7
The excess $3$ code is also called cyclic redundancy codeweighted codeself complimenting codealgebraic code
0 votes
9
In propositional logic, which of the following is equivalent to $p \rightarrow q$?$\sim p\rightarrow q$$ \sim p \vee q$$ \sim p \vee \sim q$$p\rightarrow \sim q$
0 votes
10
0 votes
11
The present ages of three persons in proportions $4:7:9$. Eight years ago, the sum of their ages was $56$. Find their present ages (in years).$8,20,28$$16,28,36$$20,35,45...
0 votes
13
3 votes
14
5 votes
16
The number of distinct 1 letter subword present in “NAMITA” is equal to_______________Answer given subwords are N,A,M,I,TBut last ‘A’ is not a subword. Is it cor...
0 votes
18
In a box, there are $2$ red, $3$ black and $4$ blue coloured balls. The probability of drawing $2$ blue balls in sequence without replacing, and then drawing $1$ black ba...
0 votes
22
Which part in 8086 microprocessor is responsible for fetching instructions into the queue?BIUEUStackRegisters
2 votes
23
What is the time complexity for insertion in binary tree in worst case?O(1)O(log n)O(n)O(n log n)
5 votes
24
What is the time complexity to delete an arbitrary node from binary heap?O(n)O(log n)O(1)O(n log n)
0 votes
26
Where can i find only maths PYQ all branches . for practice ?
1 votes
27
I did Google and found out that Quicksort is better then Mergesort, but my question is which is faster among both?
7 votes
28
0 votes
30
Let $G$ be an undirected complete graph on $n$ vertices, where $n 2$. Then, the number of different Hamiltonian cycles in $G$ is equal to$n!$$(n-1)!$$1$$\frac{(n-1)!}{2}...